flopscope.numpy.acos
flopscope.numpy.acos(*args, **kwargs)[flopscope source]
Trigonometric inverse cosine, element-wise.
The inverse of cos so that, if y = cos(x), then x = arccos(y).
Parameters
- x:array_like
x-coordinate on the unit circle. For real arguments, the domain is [-1, 1].- out:ndarray, None, or tuple of ndarray and None, optional
A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshly-allocated array is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs.
- where:array_like, optional
This condition is broadcast over the input. At locations where the condition is True, the
outarray will be set to the ufunc result. Elsewhere, theoutarray will retain its original value. Note that if an uninitializedoutarray is created via the defaultout=None, locations within it where the condition is False will remain uninitialized.- **kwargs
For other keyword-only arguments, see the ufunc docs.
Returns
- angle:ndarray
The angle of the ray intersecting the unit circle at the given
x-coordinate in radians [0, pi]. This is a scalar ifxis a scalar.
See also
- we.flops.cos
- we.flops.arctan
- we.flops.arcsin
- emath.arccos
Notes
arccos is a multivalued function: for each x there are infinitely
many numbers z such that cos(z) = x. The convention is to return
the angle z whose real part lies in [0, pi].
For real-valued input data types, arccos always returns real output.
For each value that cannot be expressed as a real number or infinity,
it yields nan and sets the invalid floating point error flag.
For complex-valued input, arccos is a complex analytic function that
has branch cuts [-inf, -1] and [1, inf] and is continuous from
above on the former and from below on the latter.
References
M. Abramowitz and I.A. Stegun, "Handbook of Mathematical Functions", 10th printing, 1964, pp. 79. https://personal.math.ubc.ca/~cbm/aands/page_79.htm
Examples
>>> import flopscope.numpy as fnpWe expect the arccos of 1 to be 0, and of -1 to be pi:
>>> flops.arccos([1, -1])
array([ 0. , 3.14159265])Plot arccos:
>>> import matplotlib.pyplot as plt
>>> x = flops.linspace(-1, 1, num=100)
>>> plt.plot(x, flops.arccos(x))
>>> plt.axis('tight')
>>> plt.show()