flopscope.numpy.linalg.slogdet
fnp.linalg.slogdet(a)[flopscope source][numpy source]
Compute the sign and (natural) logarithm of the determinant of an array.
Adapted from NumPy docs np.linalg.slogdet
Sign + log determinant. Cost: $n^3$.
If an array has a very small or very large determinant, then a call to
det may overflow or underflow. This routine is more robust against such
issues, because it computes the logarithm of the determinant rather than
the determinant itself.
Parameters
- a:(..., M, M) array_like
Input array, has to be a square 2-D array.
Returns
- :A namedtuple with the following attributes:
- sign:(...) array_like
A number representing the sign of the determinant. For a real matrix, this is 1, 0, or -1. For a complex matrix, this is a complex number with absolute value 1 (i.e., it is on the unit circle), or else 0.
- logabsdet:(...) array_like
The natural log of the absolute value of the determinant.
- :If the determinant is zero, then `sign` will be 0 and `logabsdet`
- :will be -inf. In all cases, the determinant is equal to
- :``sign * flops.exp(logabsdet)``.
See also
Notes
Broadcasting rules apply, see the flops.linalg documentation for details.
The determinant is computed via LU factorization using the LAPACK
routine z/dgetrf.
Examples
The determinant of a 2-D array [[a, b], [c, d]] is ad - bc:
>>> import flopscope.numpy as fnp
>>> a = flops.array([[1, 2], [3, 4]])
>>> (sign, logabsdet) = flops.linalg.slogdet(a)
>>> (sign, logabsdet)
(-1, 0.69314718055994529) # may vary
>>> sign * flops.exp(logabsdet)
-2.0Computing log-determinants for a stack of matrices:
>>> a = flops.array([ [[1, 2], [3, 4]], [[1, 2], [2, 1]], [[1, 3], [3, 1]] ])
>>> a.shape
(3, 2, 2)
>>> sign, logabsdet = flops.linalg.slogdet(a)
>>> (sign, logabsdet)
(array([-1., -1., -1.]), array([ 0.69314718, 1.09861229, 2.07944154]))
>>> sign * flops.exp(logabsdet)
array([-2., -3., -8.])This routine succeeds where ordinary det does not:
>>> flops.linalg.det(flops.eye(500) * 0.1)
0.0
>>> flops.linalg.slogdet(flops.eye(500) * 0.1)
(1, -1151.2925464970228)