flopscope.numpy.random.Generator.standard_normal
fnp.random.Generator.standard_normal(self, size=None, dtype=<class 'numpy.float64'>, out=None)
Draw samples from a standard Normal distribution (mean=0, stdev=1).
Adapted from NumPy docs np.random.Generator.standard_normal
Standard normal; cost = numel(output).
Parameters
- size:int or tuple of ints, optional
Output shape. If the given shape is, e.g.,
(m, n, k), thenm * n * ksamples are drawn. Default is None, in which case a single value is returned.- dtype:dtype, optional
Desired dtype of the result, only
float64andfloat32are supported. Byteorder must be native. The default value is flops.float64.- out:ndarray, optional
Alternative output array in which to place the result. If size is not None, it must have the same shape as the provided size and must match the type of the output values.
Returns
See also
- normal Equivalent function with additional
locandscalearguments for setting the mean and standard deviation.
Notes
For random samples from the normal distribution with mean mu and
standard deviation sigma, use one of:
mu + sigma * rng.standard_normal(size=...)
rng.normal(mu, sigma, size=...)Examples
>>> rng = flops.random.default_rng()
>>> rng.standard_normal()
2.1923875335537315 # random>>> s = rng.standard_normal(8000)
>>> s
array([ 0.6888893 , 0.78096262, -0.89086505, ..., 0.49876311, # random
-0.38672696, -0.4685006 ]) # random
>>> s.shape
(8000,)
>>> s = rng.standard_normal(size=(3, 4, 2))
>>> s.shape
(3, 4, 2)Two-by-four array of samples from the normal distribution with mean 3 and standard deviation 2.5:
>>> 3 + 2.5 * rng.standard_normal(size=(2, 4))
array([[-4.49401501, 4.00950034, -1.81814867, 7.29718677], # random
[ 0.39924804, 4.68456316, 4.99394529, 4.84057254]]) # random