flopscope.numpy.true_divide
fnp.true_divide(*args, **kwargs)[flopscope source][numpy source]
Divide arguments element-wise.
Adapted from NumPy docs np.true_divide
Element-wise true division (explicit).
Parameters
- x1:array_like
Dividend array.
- x2:array_like
Divisor array. If
x1.shape != x2.shape, they must be broadcastable to a common shape (which becomes the shape of the output).- out:ndarray, None, or tuple of ndarray and None, optional
A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshly-allocated array is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs.
- where:array_like, optional
This condition is broadcast over the input. At locations where the condition is True, the
outarray will be set to the ufunc result. Elsewhere, theoutarray will retain its original value. Note that if an uninitializedoutarray is created via the defaultout=None, locations within it where the condition is False will remain uninitialized.- **kwargs
For other keyword-only arguments, see the ufunc docs.
Returns
- y:ndarray or scalar
The quotient
x1/x2, element-wise. This is a scalar if bothx1andx2are scalars.
See also
- seterr Set whether to raise or warn on overflow, underflow and division by zero.
Notes
Equivalent to x1 / x2 in terms of array-broadcasting.
The true_divide(x1, x2) function is an alias for
divide(x1, x2).
Examples
>>> import flopscope.numpy as fnp
>>> flops.divide(2.0, 4.0)
0.5
>>> x1 = flops.arange(9.0).reshape((3, 3))
>>> x2 = flops.arange(3.0)
>>> flops.divide(x1, x2)
array([[nan, 1. , 1. ],
[inf, 4. , 2.5],
[inf, 7. , 4. ]])The / operator can be used as a shorthand for flops.divide on
ndarrays.
>>> x1 = flops.arange(9.0).reshape((3, 3))
>>> x2 = 2 * flops.ones(3)
>>> x1 / x2
array([[0. , 0.5, 1. ],
[1.5, 2. , 2.5],
[3. , 3.5, 4. ]])