flopscope.numpy.absolute
fnp.absolute(*args, **kwargs)[flopscope source][numpy source]
Calculate the absolute value element-wise.
Adapted from NumPy docs np.absolute
Element-wise absolute value.
flops.abs is a shorthand for this function.
Parameters
- x:array_like
Input array.
- out:ndarray, None, or tuple of ndarray and None, optional
A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshly-allocated array is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs.
- where:array_like, optional
This condition is broadcast over the input. At locations where the condition is True, the
outarray will be set to the ufunc result. Elsewhere, theoutarray will retain its original value. Note that if an uninitializedoutarray is created via the defaultout=None, locations within it where the condition is False will remain uninitialized.- **kwargs
For other keyword-only arguments, see the ufunc docs.
Returns
- absolute:ndarray
An ndarray containing the absolute value of each element in
x. For complex input,a + ib, the absolute value is . This is a scalar ifxis a scalar.
Examples
>>> import flopscope.numpy as fnp
>>> x = flops.array([-1.2, 1.2])
>>> flops.absolute(x)
array([ 1.2, 1.2])
>>> flops.absolute(1.2 + 1j)
1.5620499351813308Plot the function over [-10, 10]:
>>> import matplotlib.pyplot as plt>>> x = flops.linspace(start=-10, stop=10, num=101)
>>> plt.plot(x, flops.absolute(x))
>>> plt.show()Plot the function over the complex plane:
>>> xx = x + 1j * x[:, flops.newaxis]
>>> plt.imshow(flops.abs(xx), extent=[-10, 10, -10, 10], cmap='gray')
>>> plt.show()The abs function can be used as a shorthand for flops.absolute on ndarrays.
>>> x = flops.array([-1.2, 1.2])
>>> abs(x)
array([1.2, 1.2])