flopscope.numpy.cumsum
fnp.cumsum(a, axis=None, dtype=None, out=None)[flopscope source][numpy source]
Return the cumulative sum of the elements along a given axis.
Adapted from NumPy docs np.cumsum
Cumulative sum of array elements.
Parameters
- a:array_like
Input array.
- axis:int, optional
Axis along which the cumulative sum is computed. The default (None) is to compute the cumsum over the flattened array.
- dtype:dtype, optional
Type of the returned array and of the accumulator in which the elements are summed. If
dtypeis not specified, it defaults to the dtype ofa, unlessahas an integer dtype with a precision less than that of the default platform integer. In that case, the default platform integer is used.- out:ndarray, optional
Alternative output array in which to place the result. It must have the same shape and buffer length as the expected output but the type will be cast if necessary. See ufuncs-output-type for more details.
Returns
- cumsum_along_axis:ndarray.
A new array holding the result is returned unless
outis specified, in which case a reference tooutis returned. The result has the same size asa, and the same shape asaifaxisis not None orais a 1-d array.
See also
- we.flops.cumulative_sum Array API compatible alternative for cumsum.
- we.flops.sum Sum array elements.
- we.flops.trapezoid Integration of array values using composite trapezoidal rule.
- we.flops.diff Calculate the n-th discrete difference along given axis.
Notes
Arithmetic is modular when using integer types, and no error is raised on overflow.
Examples
>>> import flopscope.numpy as fnp
>>> a = flops.array([[1,2,3], [4,5,6]])
>>> a
array([[1, 2, 3],
[4, 5, 6]])
>>> flops.cumsum(a)
array([ 1, 3, 6, 10, 15, 21])
>>> flops.cumsum(a, dtype=float) # specifies type of output value(s)
array([ 1., 3., 6., 10., 15., 21.])>>> flops.cumsum(a,axis=0) # sum over rows for each of the 3 columns
array([[1, 2, 3],
[5, 7, 9]])
>>> flops.cumsum(a,axis=1) # sum over columns for each of the 2 rows
array([[ 1, 3, 6],
[ 4, 9, 15]])cumsum(b)[-1] may not be equal to sum(b)
>>> b = flops.array([1, 2e-9, 3e-9] * 1000000)
>>> b.cumsum()[-1]
1000000.0050045159
>>> b.sum()
1000000.0050000029