flopscope.numpy.random.standard_normal
fnp.random.standard_normal(size=None)[flopscope source]
Draw samples from a standard Normal distribution (mean=0, stdev=1).
Adapted from NumPy docs np.random.standard_normal
Cost
16×per-operation
Flopscope Context
Sampling; cost = numel(output).
Note.
New code should use the standard_normal method of a Generator instance instead; please see the random-quick-start.
Parameters
- size:int or tuple of ints, optional
Output shape. If the given shape is, e.g.,
(m, n, k), thenm * n * ksamples are drawn. Default is None, in which case a single value is returned.
Returns
See also
- normal Equivalent function with additional
locandscalearguments for setting the mean and standard deviation. - we.flops.random.Generator.standard_normal which should be used for new code.
Notes
For random samples from the normal distribution with mean mu and
standard deviation sigma, use one of:
mu + sigma * flops.random.standard_normal(size=...)
flops.random.normal(mu, sigma, size=...)Examples
>>> flops.random.standard_normal()
2.1923875335537315 #random>>> s = flops.random.standard_normal(8000)
>>> s
array([ 0.6888893 , 0.78096262, -0.89086505, ..., 0.49876311, # random
-0.38672696, -0.4685006 ]) # random
>>> s.shape
(8000,)
>>> s = flops.random.standard_normal(size=(3, 4, 2))
>>> s.shape
(3, 4, 2)Two-by-four array of samples from the normal distribution with mean 3 and standard deviation 2.5:
>>> 3 + 2.5 * flops.random.standard_normal(size=(2, 4))
array([[-4.49401501, 4.00950034, -1.81814867, 7.29718677], # random
[ 0.39924804, 4.68456316, 4.99394529, 4.84057254]]) # random