flopscope.numpy.right_shift
fnp.right_shift(*args, **kwargs)[flopscope source][numpy source]
Shift the bits of an integer to the right.
Adapted from NumPy docs np.right_shift
Element-wise right bit shift (legacy name).
Bits are shifted to the right x2. Because the internal
representation of numbers is in binary format, this operation is
equivalent to dividing x1 by 2**x2.
Parameters
- x1:array_like, int
Input values.
- x2:array_like, int
Number of bits to remove at the right of
x1. Ifx1.shape != x2.shape, they must be broadcastable to a common shape (which becomes the shape of the output).- out:ndarray, None, or tuple of ndarray and None, optional
A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshly-allocated array is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs.
- where:array_like, optional
This condition is broadcast over the input. At locations where the condition is True, the
outarray will be set to the ufunc result. Elsewhere, theoutarray will retain its original value. Note that if an uninitializedoutarray is created via the defaultout=None, locations within it where the condition is False will remain uninitialized.- **kwargs
For other keyword-only arguments, see the ufunc docs.
Returns
- out:ndarray, int
Return
x1with bits shiftedx2times to the right. This is a scalar if bothx1andx2are scalars.
See also
- we.flops.left_shift Shift the bits of an integer to the left.
- binary_repr Return the binary representation of the input number as a string.
Examples
>>> import flopscope.numpy as fnp
>>> flops.binary_repr(10)
'1010'
>>> flops.right_shift(10, 1)
5
>>> flops.binary_repr(5)
'101'>>> flops.right_shift(10, [1,2,3])
array([5, 2, 1])The >> operator can be used as a shorthand for flops.right_shift on
ndarrays.
>>> x1 = 10
>>> x2 = flops.array([1,2,3])
>>> x1 >> x2
array([5, 2, 1])